1/2x^2-3x+c=0

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Solution for 1/2x^2-3x+c=0 equation: 


x in (-oo:+oo)

c+(1/2)*x^2-(3*x) = 0

c+(1/2)*x^2-3*x = 0

c+1/2*x^2-3*x = 0

DELTA = (-3)^2-(1/2*4*c)

DELTA = 9-2*c

9-2*c = 0

9-2*c = 0 // - 9

-2*c = -9 // : -2

c = -9/(-2)

c = 9/2

DELTA = 0  <=>  t_1 = 9/2

x = 3/(1/2*2) i c = 9/2

x = 3 i c = 9/2

( x = ((9-2*c)^(1/2)+3)/(1/2*2) or x = (3-(9-2*c)^(1/2))/(1/2*2) ) i c > 9/2

( x = (9-2*c)^(1/2)+3 or x = 3-(9-2*c)^(1/2) ) i c > 9/2

c-9/2 > 0

c-9/2 > 0 // + 9/2

c > 9/2

x in { 3, (9-2*c)^(1/2)+3, 3-(9-2*c)^(1/2) }

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